First-Order ODEs
TertiaryDifferential Equations
Concept
Separable, linear, and exact first-order ordinary differential equations.
Walkthrough
Solve dy/dx = 2x with y(0) = 1.
- 1.This is a separable ODE. Rearrange so all y terms are on one side and x terms on the other.
- 2.Separate: dy = 2x dx.
- 3.Integrate both sides: ∫dy = ∫2x dx, which gives y = x² + C.
- 4.Apply the initial condition y(0) = 1: 1 = (0)² + C, so C = 1.
- 5.So the solution is y = x² + 1.
Answer
y = x² + 1
Ready to try some problems? Switch to Practice mode.
